1686B - Odd Subarrays - CodeForces Solution


dp greedy *800

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Python Code:

for _ in range(int(input())):
	n= int(input())
	x= list(map(int,input().split()))
	count=0
	i = 0
	while i<n-1:
		if x[i]>x[i+1]:
			count+= 1
			i+= 1
		i+= 1
	print(count)

C++ Code:

#include<bits/stdc++.h>
using namespace std;
int main()
{
	int t,n,a[100010];
	cin>>t;
	while(t--)
	{
		int ans=0;
		cin>>n;
		for(int i=1;i<=n;i++)  cin>>a[i];
		for(int i=1;i<n;i++)
		{
			if(a[i]>a[i+1])
			{
				ans++;
				i++;
			}
		}
		cout<<ans<<endl;
	}
}


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